Question

Найдите модуль и аргумент числа 8+2i/5-3i

Answer 1

z=(8+2i)/(5-3i)=(8+2i)(5+3i)/[(5-3i)(5+3i)]=(40+24i+10i-6)/(25+9)=
=(34+34i)/34=1+i
|z|=√(1+1)=√2
argφ=arctg1
φ=Π/4