Question

2^(x+2)+3*2^(x+1)+2^(x)=68 помогите

Answer 1

$2^{x}*2^{2} + 3* 2^{x}*2 + 2^{x} = 68 \ 2^{x} (4 + 6 + 1) = 68 \ 2^{x} *11 = 68 \ 2^{x} = frac{68}{11} \ x = log_{2}( frac{68}{11} )$

$x = log_{2}( frac{68}{11} )$ ≈ 2.62803122261304