Question

(9в^2/9-в^2)/(3в/6-2в)

Answer 1

= ( 9в^2 / ( 3 - в )( 3 + в )) • ( 3в / ( 2( 3 - в )) = 3в / ( 2( 3 + в )) = 3в / ( 6 + 2в )

Answer 2

=(9в^2/(3-в)(3+в)) ÷(3в/2(3-в))=
=9в^2×2(3-в)/3в(3-в)(3+в)=
=6в/(3+в)