Question

ПОМОГИТЕ ДАМ 20 БАЛЛОВ!
y = 1/arccos^2x

Answer 1

$y=frac{1}{arccos^2x}\\y'=-frac{1}{arccos^4x}cdot 2arccosxcdot frac{-1}{sqrt{1-x^2}}=frac{2}{sqrt{1-x^2}, cdot arccos^3x}$