Question

упростите : log12 6 + log12 24 + 7 в степени log7 2

Answer 1

$log_{12}6+log_{12}24+7^{log_72}=log_{12}(6cdot 24)+2=log_{12}144+2=\\=log_{12}12^2+2=2log_{12}12+2=2+2=4$

Answer 2

LOG12 (6*24)+2=LOG12 144+2=2+2=4