Предмет: Физика, автор: Jiyong

автомобиль массой 2,1 т движется по шоссе со скоростью 45 км/ч. Чему равна его кинетическая энергия? Вычисления произвести в системе "СИ"

Ответы

Автор ответа: IZUBR

Дано:
m=2,1 тонны=2100 кг.
V=45 км/ч=12,5 м/с.
E(кин)=?
____________
Решение:
Формула кинетической энергии:
$E_{kun}= frac{m*V^2}{2};$
Считаем:
$E_{kun}=frac{2100*12,5^2}{2}=164062,5.$
Получаем ответ: кинетическая энергия автомобиля равна 164062,5 Дж или 164 кДж.

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