Question

1)$frac{sqrt[3]{9} *3^5} {15^0 * 27^2 *3^ -frac{1}{3}}$
2)$(sqrt[3]{2 sqrt{16} } )^2$

Answer 1

$frac{sqrt[3]{9} *3^5} {15^0 * 27^2 *3^ -frac{1}{3}} = frac{3^{ frac{2}{3}}*3^5 }{1*(3^3)^2*3^{- frac{1}{3} }} = frac{3^{ frac{17}{3} }}{3^{ frac{17}{3} }}=1$

$(sqrt[3]{2 sqrt{16} })^2=( sqrt[3]{2 sqrt{2^4} })^2=( sqrt[3]{2*2^2})^2=( sqrt[3]{2^3})^2=2^2=4$