Question

решите уравнение 2^cos x+sin 2x+5=32

Answer 1

сosx+sin2x+5=5
cosx+2sinxcosx=0
cosx(1+2sinx)=0
cosx=0⇒x=π/2+πn,n∈z
sinx=-1/2⇒x=(-1)^(k+1)*π/6+πk,k∈z