Question

4x^2-9>0
зарание спосибо

Answer 1

$4x^2-9 textgreater 0, \ x^2-frac{9}{4} textgreater 0, \ x^2-(frac{3}{2})^2 textgreater 0, \ (x+frac{3}{2})(x-frac{3}{2}) textgreater 0, \ left [ {{ left { {{x+frac{3}{2} textless 0,} atop {x-frac{3}{2} textless 0;}} right. } atop { left { {{x+frac{3}{2} textgreater 0,} atop {x-frac{3}{2} textgreater 0;}} right. }} right. left [ {{ left { {{x textless -frac{3}{2},} atop {x textless frac{3}{2};}} right. } atop { left { {{x textgreater -frac{3}{2},} atop {x textgreater frac{3}{2};}} right. }} right. left [ {{x textless -frac{3}{2},} atop {x textgreater frac{3}{2};}} right. \ xin(-infty;-frac{3}{2})cup(frac{3}{2};+infty)$