Предмет: Химия, автор: Veronu15

Смесь порошка алюминия массой 32,4 г и порошка серы массой 48 г сильно нагрели в тигле без доступа воздуха.После этого к оставшему содержимому тигля добавили избыток соляной кислоты Какой объем кислорода (н.у) потребуется для сжигания выделившегося газа?

Ответы

Автор ответа: ndambaeva

2Al+3S=Al2S3
Al2S3+6HCl=2AlCl3+3H2S
H2S+1.5O2=H2O+SO2

nAl=32.4/64=0.6mol isbytok
nS=48/96=0.5mol

1molS=2molO2
48g xL
S - 2O2
96g 44.8L

x=48*44.8/96=22.4L

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