Question

log3(x^2-3x)=log3(12-4x)

Answer 1

ОДЗ
x²-3x>0⇒x(x-3)>0⇒x<0 U x>3
12-4x>0⇒4x<12⇒x<3
x∈(-∞;0)
x²-3x=12-4x
x²+x-12=0
x1+x2=-1 U x1*x2=-12
x1=-4
x2=3 не удов усл