Question

найти область определения функции y=√(log2 (x-6))

Answer 1

$y=sqrt{log_2(x-6)}, \ left { {{log_2(x-6)geq0,} atop {x-6 textgreater 0,}} right. left { {{x-6geq1,} atop {x-6 textgreater 0,}} right. left { {{xgeq7,} atop {x textgreater 6,}} right. \ xgeq7, \ xin(7;+infty).$