Question

Упростить и решить:
7*(4a^5+2ab)=

2a^7*(5a^3+0,4ab)=

(1,4x^2-3,5y)*(-2/7x)=

0,5ab(-2)*3+a-2a^2+3a-2=

Answer 1

7*(4а^5+2ab)=28a^5+14ab
2a^7*(5a^3+0.4ab)=10a^10+0.8a^8b
(1.4x^2-3.5y)*(-2/7x)=-0.4x^3+xy
0.5ab(-2)*3+a-2a^2+3a-2=-3ab+4a-2a^2-2