Question

Решите систему уравнений:
$3^{x}$*$2^{y}$=2
y+x=1

Answer 1

$begin{cases} y=1-x \ 3^x*2^{1-x}=2 end{cases} textless = textgreater begin{cases} y=1-x \ (frac{3}{2})^x*2=2 end{cases} textless = textgreater begin{cases} y=1-x \ (frac{3}{2})^x=1 end{cases}\ textless = textgreater begin{cases} x=0 \ y=1-x end{cases} textless = textgreater begin{cases} x=0 \ y=1 end{cases}$
Ответ: (0; 1)