Question

помогите 11 задание пожалуйста!!!

Answer 1

x²-2y²-xy+3x+3y=x² - xy - 2y² + 3x+3y=

=x² -(3xy-2xy) - (3y² - y²) +3x+3y=

=x² - 3xy+2xy - 3y²+y²+3x+3y=

=x²+2xy+y²-3xy-3y²+3x+3y=
=(x²+2xy+y²)-(3xy+3y²)+(3x+3y)=
=(x+y)²-3y(x+y)+3(x+y)=
=(x+y)(x+y-3y+3)=
=(x+y)(x-2y+3)