Question

Объясните мне по какой системе решается номер 5))

Answer 1

$left { {{3(x-1+frac{4-3x}{4}-(1-2(x-1-frac{x+2}{5})))leq5x-7,} atop {frac{x^2+8x+7}{x^2+2x+1}-1leq0;}} right. \ 60(x-1+frac{4-3x}{4}-(1-2(x-1-frac{x+2}{5})))leq100x-140, \ 60x-60+15(4-3x)-60(1-2(x-1-frac{x+2}{5}))leq100x-140, \ 60x-60+60-45x-60+120(x-1-frac{x+2}{5})leq100x-140, \ 15x-60+120x-120-24(x+2)leq100x-140, \ 135x-180-24x-48leq100x-140, \ 111x-100xleq228-140, \ 11x leq 88, \ x leq 8;$
$frac{(x+7)(x+1)-(x+1)^2}{(x+1)^2}leq0, \ x+1neq0, xneq-1, \ frac{(x+1)(x+7-x-1)}{(x+1)^2}leq0, \ frac{6(x+1)}{(x+1)^2}leq0, \ frac{1}{x+1}leq0, \ x+1 textless 0, \ x textless -1; \ left { {{xleq8,} atop {x textless -1;}} right. \ x textless -1, \ xin(infty;-1).$