Question

Решите систему уравнений
x-y-4=0 ;l
lo2x-log2y=1

Answer 1

x>0 U y>0
x=y+4
log(2)(y+4)-log(2)y=1
log(2)[(y+4)/y]=1
(y+4)/y=2
(y+4-2y)=0
4-y=0
y=4
x=8
(8;4)