Question

Помогите, пожалуйстааааааа!!!!!

Answer 1

$frac{x}{x+1} - frac{9x+13}{x^2-2x-3} = frac{5}{3-x}, \ frac{x}{x+1} - frac{9x+13}{(x+1)(x-3)} + frac{5}{x-3} = 0, \ frac{x(x-3)-(9x+13)+5(x+1)}{(x+1)(x-3)} = 0, \ left { {{x+1 neq 0,} atop {x-3 neq 0;}} right. left { {{x neq -1,} atop {x neq 3;}} right. \ x^2-3x-9x-13+5x+5=0, \ x^2-7x-8=0, \ x_1=-1, x_2=8, \ x=8.$

Answer 2

$frac{x}{x+1}- frac{9x+13}{x^2-2x-3}= frac{5}{3-x}$
$frac{x}{x+1}- frac{9x+13}{(x+1)(x-3)}+ frac{5}{x-3}=0$
$frac{x(x-3)-9x-13+5(x+1)}{(x+1)(x-3)}=0$
$frac{x^2-3x-9x-13+5x+5}{(x+1)(x-3)}=0$
$frac{x^2-7x-8}{(x+1)(x-3)}=0$
$frac{(x+1)(x-8)}{(x+1)(x-3)}=0$
$frac{x-8}{x-3}=0$
x-8=0
x=8