Question

2sin(π/6-3x)-1=0.)))))))))))

Answer 1

$2sin(frac{pi}{6}-3x)=1\\sin(frac{pi}{6}-3x)=frac{1}{2}\\frac{pi}{6}-3x=(-1)^{k}cdot frac{pi}{6}+pi n,; nin Z\\3x=frac{pi}{6}-(-1)^{k}cdot frac{pi}{6}-pi n; ,; nin Z\\x=frac{pi}{18}+(-1)^{k+1}cdot frac{pi}{18}+frac{pi n}{2}; ,; nin Z$