Question

$3 x^{2} -27=0$

Answer 1

$3x^2-27=0\3(x^2-9)=0\x^2-9=frac{0}{3}\x^2-3^2=0\(x-3)(x+3)=0\x_1=3;\x_2=-3.$

Answer 2

3х^2 - 27 = 0
3•( х^2 - 9 ) = 0
3•( х - 3 )•( х + 3 ) = 0
х - 3 = 0 ; х = 3
х + 3 = 0 ; х = - 3
Ответ 3 ; - 3