Question

cos2x+3sinx-2=0
sin2x-6sinx=0

Answer 1

1)cos2x+3sinx-2=0
1-2sin²x+3sinx-2=0
sinx=a
2a²-3a+1=0
D=1
a=1; sinx=1 ⇒x=π/2+2πn
a=1/2; sinx=1/2⇒x=(-1)ⁿπ/6+πn
2)sin2x-6sinx=0
2sinx*cosx-6sinx=0
2sinx(cosx-3)=0
sinx=0
x=πn