Question

Решите неравенство:$frac{1}{9} ^{ frac{4-x^{2} }{2} } geq 27 ^{x}$

Answer 1

(3^-2)^[(4-x²)/2]≥(3³)^x
3^(x²-4)≥3^3x
x²-4≥3x
x²-3x-4≥0
x1+x2=3 U x1*x2=-4
x1=-1 U x2=4
x∈(-∞;-1] U [4;∞)