Question

∫от 0 до 12 3*(2Х-12)^2=

Answer 1

$intlimits^{12}_0 {3cdot (2x-12)^2} , dx =3cdot frac{1}{2}cdot frac{(2x-12)^3}{3} , left |_0^{12}=frac{1}{2}cdot (12^3-(-12)^3)=$

$=frac{1}{2}cdot (12^3+12^3)=frac{1}{2}cdot 2cdot 12^3=12^3=1728$