Question

36cos квадрат при tg=-1

Answer 1

$1+ tg^{2} x= frac{1}{cos ^{2} x} 1+(-1) ^{2} = frac{1}{cos ^{2}x } cos ^{2} x= frac{1}{2}$
$36*cos ^{2} =36* frac{1}{2} =18$