Question

Решение систем уравнений второй степени

Answer 1

y^2 - 2x = 13
X + y = - 15
Решение
2x = y^2 - 13
X = - 5 - y
2x = - 10 - 2y
y^2 - 13 = - 10 - 2y
y^2 + 2y - 3 = 0
D = 4 + 12 = 16 ; VD = 4
y1 = ( - 2 + 4 ) : 2 = 1
y2 = ( - 2 - 4 ) : 2 = - 3
X = - 5 - y
X1 = - 5 - 1 = - 6
X2 = - 5 + 3 = - 2
Ответ ( - 6 ; 1 ) ; ( - 2 ; - 3 )