Question

Sinx-sin2x=cos2x
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Answer 1

sinx-sin2x=cos2x
sinx - 2sinxcosx = 1 - 2$sin^{2}x$
2$sin^{2}x$ - 2sinxcosx + sinx = 1
$(sinx-cosx)^{2}$ = -sinx
1=sinx
x=0