Question

ПОМОГИТЕ ПОЖАЛУЙСТА
3. Вычислить:
1)24arccos (√3/2) - 4arcsin (-√2/2) = ?
2)(1/5)arccos (-0.5) + (1/3)arccos 0 = ?

Answer 1

1)24arccos (√3/2) - 4arcsin (-√2/2) =24*π/6-4*(-π/4)=4π+π=5π
2)(1/5)arccos (-0.5) + (1/3)arccos 0 =1/5*2π/3+1/3*π/2=2π/15+π/6=
=(4π+5π)/30=9π/30=3π/10