Question

решите уравнение и найдите х..
sin п(8x-9)=-1

Answer 1

π(8x-9)=-π/2+2πn, n€Z
8x-9=-1/2+2n, n€Z
8x=17/2+2n, n€Z
x=17/16+n/4, n€Z

Answer 2

$pi (8x-9)=- frac{ pi }{2} +2 pi k \ 8x-9= -frac{1}{2} +2k \ 8x=9- frac{1}{2} +2k \ 8x= frac{17}{2} +2k \ x= frac{17}{16} + frac{k}{4} ,$
k∈Z