Question

(x^3-x^2+x-1)/(x+8)<0

Answer 1

[x²(x-1)+(x-1)]/(x+8)<0
(x²+1)(x-1)/(x+8)<0
x²+1>0 при любом х⇒(x-1)/(x+8)<0
x=1  x=-8
x∈(-8;1)