Question

Решите плиззз
(3x+1)^2=5(x+1/3)

Answer 1

(3x+1)^2=5(x+1/3)
9x^2+6x+1=5x+5/3
9x^2+6x+1-5x-5/3-=0
9x^2+x-2/3=0
D=1^2-4*9*(-2/3)=1+24=25
x1=-1^+5/2*9=2/9
x2=-1-5/2*9=-1/3

Answer 2

(3х+1)²=5(х+1/3)
9х²+6х+1=5х+5/3
9х²+6х-5х+1- 5/3=0
9х²+х-2/3=0 /*3
27х²+3х-2=0
D=3+4*2*27=225
х1=(-3+15)/(2*27)=12/54=2/9
х2=(-3-15)/54=-18/54=-1/3
ответ: -1/3, 2/9