Question

РЕШИТЬ ..................

Answer 1

$(frac{2a+1}{2a-1}-frac{2a-1}{2a+1}):frac{2a}{6a+3}=\ (frac{2a+1}{2a-1}*frac{2a-1}{1}-frac{2a-1}{2a+1}*frac{2a-1}{1})*frac{6a+3}{2a}=\ (2a+1-frac{(2a-1)^2}{2a+1})*frac{6a+3}{2a}=\ (2a+1-frac{(2a+1)^2}{2a+1})*frac{6a+3}{2a}=\ (2a+1-(2a+1))*frac{6a+3}{2a}=\ (2a+1-2a-1)*frac{6a+3}{2a}=\ 0*frac{6a+3}{2a}=0$