Question

Решите функцию:
2х^2-х=у
2х-1=у

Answer 1

2х^2 - х = y
2x - 1 = y
2x^2 - x = 2x - 1
2x^2 - 3x + 1 = 0
D = 9 - 8 = 1
X1 = ( 3 + 1 ) : 4 = 1
X2 = ( 3 - 1 ) : 4 = 0,5
y1 = 2 - 1 = 1
y2 = 1 - 1 = 0
Ответ ( 1 ; 1 ) ; ( 0,5 ; 0 )