Question

Ребят решите пж x^4=(x-6)^2

Answer 1

$x^4=(x-6)^2\\(x^2)^2-(x-6)^2=0\\(x^2-x+6)(x^2+x-6)=0\\x^2-x+6=0; ; to ; ; D=-23 textless 0; to ; net; reshenij\\(x^2-x+6)(x-2)(x+3)=0\\x_1=2; ,; ; x_2=-3$