Question

решите систему {3x^2+y=6 {4x^2-y=1

Answer 1

$left { {{3x^2+y=6} atop {4x^2-y=1}} right. ; oplus ; left { {{3x^2+y=6} atop {7x^2=7}} right. ; left { {{3x^2+y=6} atop {x^2=1}} right. ; left { {{y=6-3x^2} atop {x^2=1}} right. ; left { {{y=3} atop {x=pm 1}} right. \\Otvet:quad (-1,3); ,; (1,3); .$