Question

Решите неравенство: $frac{2}{ x^{2} +7x+6} leq frac{4}{x^{2}+7x+6 }$

Answer 1

2(x^2+7x+6)<=4(x^2+7X+6)
2x^2+14x+12<=4x^2+28x+24
2x^2-4x^2+14x-28x<=24-12
-2x^2-14x<=12
-2x(x+7)<=12
-2x<=12       x+7=12
-x<=6             x<=5
x>=-6
x[-6;5]