Question

A^2-9/6a^2-18a при a=-0.3

Answer 1

$frac{ a^{2}-9 }{6a ^{2} -18a} = frac{(a-3)(a+3)}{6a(a-3)} = frac{a+3}{6a} \ a=-0.3 \ \ frac{-0.3+3}{6*(-0.3)} = frac{2.7}{-1.8} =-1.5$