Предмет: Химия, автор: джезефина1

сколько граммов соли нитрата натрия образуется пои взаимодействии 65 г. гидраксида натрия с пзотной кислотой?

Ответы

Автор ответа: AlenaDo

0

1)n(NaOH) = m/M = 65г / 40г/моль = 1,625 моль
2) NaOH + HNO3 = NaNO3 + H2O
n(NaNO3) = 1,625 моль
3) m(NaNO3) = n*M = 1,625 моль *85г/моль = 138,135г

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