Question

Буду благодарен за решение. .

Answer 1

sin12x=1/2*sinx-√3/2*cosx
sin12x=sin(x-π/3)
{12x=x-π/3+2πn⇒[11x=-π/3+2πn⇒[x=-π/33+2πn/11
{12x=π-x+π/3+2πn⇒[13x=4π/3+2πn⇒[x=4π/39+2πn/13,n∈Z

Answer 2

$sin12x= frac{1}{2} *sinx- frac{ sqrt{3} }{2} *cosx$
$sin12x=sin(x- frac{ pi }{3} )$
$12x=x- frac{ pi }{3} +2 pi n = textgreater 11x=-frac{ pi }{3} +2 pin = textgreater x=- frac{ pi }{33} + frac{2 pi n}{11}$
$12x= pi -x+ frac{ pi }{3} +2 pi n= textgreater 13x= frac{4 pi }{3} +2 pin= textgreater x= frac{4 pi }{39} + frac{2 pi n}{13}$,n∈Z