Question

нужна помощь срочно

Answer 1

b) (x+3)(x -4) = -12

x²-4x+3x-12 +12 =0

x² -x =0

x(x -1) =0
x =0,
x -1 =0,
x =1

ответ: x =0, x =1

a) x²(1/27) -1/3 =0

1/3(x² *1/9 -1) =0

(x² -9)/9 =0

x² -9 =0

(x -3)(x +3) =0

x -3 =0, x =3
x+3 =0, x= -3

ответ: x = -3, x =3