Question

решите систему уравнений 2(3х-у)=2х-3(1+у)23+4у=10-(х-2у)

Answer 1

{6х-2у=2х-3-3у
{23+4у=10-х+2у


{6х-2х-2у+3у=-3
{х+4у-2у=-23+10

{4х+у=-3 /-2
{х+2у=-13

{-8х-2у=6
{х+2у=-13
________
-7х=-7
х=1

1+2у=-13
2у=-13-1
2у=-14
у=-7