Question

решите уравнение (y/5x-5x/y):(y+5x) при х=1/7 , у 1/4

Answer 1

(y^2-25x^2)/5xy:(y+5x)=
(y-5x)(y+5x)/5xy:(y+5x)=
(y-5x)/5xy=
(1/4-5/7)/(5/28)=
((7-20)/28):(5/28)=
-13/28*28/5=-13/5=-2, 6

Answer 2

1)у5х-5ху=у в2-25х в2=(у-5х)(у+5х)
2)(у-5х)(у+5х):(у+5х)=у-5х
при х=17; у=14
14-5*17=14-57=728-2028=-1328