Question

Решите уравнение,пожалуйста)

Answer 1

$left { {{x+y=3} atop {y^2-x=39}} right. textless = textgreater left { {{x=3-y} atop {y^2-(3-y)=39}} right. \y^2-(3-y)=39\y^2-3+y-39=0\y^2+y-42=0\D=1-4*(-42)=169=13^2\y_1= frac{-1-13}{2} =-7\y_2= frac{-1+13}{2} =6\ left { {{y_1=-7} atop {x_1=10}} right.\ left { {{y_2=6} atop {x_2=-3}} right.$