Question

найти x (1/125) ^0,2x+1=25

Answer 1

$( frac{1}{125} )^{0,2x+1}=25\\(5^{-3})^{0,2x+1}=5^2\\-0,6x-3=2\\-0,6x=5\\x=- frac{50}{6} \\x=-8frac{1}{3}$