Question

Дана функция  y = f(x), где f(x)= - 3x + 2. Найдите:
a) f(0),  f(2/3), f(-3), f(-1/2)

Answer 1

f(0)=-3*0+2=2
f(2/3)=-3*2/3+2=0
f(-3)=-3*(-3)+2= 11

f(-1/2)=-3*(-1/2)+2=3/2+2=1,5+2=3,5