Предмет: Геометрия, автор: bertain

Найдите ординату вершины параболы, которая является графиком функции у = –х² + 2

Ответы

Автор ответа: ahta

0

y=-2x²+2
y'=-4x, -4x=0, x=0, y(0)=-2*0²+2=2
(0;2) - вершина параболы
Ответ: ордината параболы у=2

Автор ответа: LFP

0

абсцисса вершины х₀ = -b / (2a) = 0
ордината вершины у₀ = у(х₀) = 2

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