Question

решите систему уравнений4y^2+x^2-4xy+x+4y-2=0 2y-x+3=0

Answer 1

{x=2y+3
{4y²+(2y+3)²-4y(2y+3)+(2y+3)+4y-2=0
4y²+4y²+12y+9-8y²-12y+2y+3+4y-2=0
6y+10=0
6y=-10
y=-10/6 = -1 2/3
x= 2*(-1 2/3) + 3 =2*(-5/3)+3=-10/3 + 3 = -2 4/3 + 2 3/3 = - 1/3