Question

УПРОСТИТЕ :
y(2 степень)+x(2 степень)-2xy
________________________
xz-yz+ty-xt 

Answer 1

frac{y^2+x^2-2xy}{xz-yz+ty-xt}=frac{(x-y)^2}{(xz-yz)+(ty-xt)}=frac{(x-y)^2}{z(x-y)+t(y-x)}=frac{(x-y)^2}{(z+t)(x-y)}=frac{(x-y)}{(z+t)}$frac{y^2+x^2-2xy}{xz-yz+ty-xt}=frac{(x-y)^2}{(xz-yz)+(ty-xt)}=frac{(x-y)^2}{z(x-y)+t(y-x)}=frac{(x-y)^2}{(z+t)(x-y)}=frac{(x-y)}{(z+t)}$

 

 

(x-y)^2=(y-x)^2