Question

найдите значение выражения $frac{27b^2+108b+108}{b} : ( frac{6}{b} +3 ) при b = - frac{4}{9}$27$b^{2}$+108b+108

Answer 1

$b=-frac{4}{9}; ;\\ frac{27b^2+108b+108}{b} :(frac{6}{b}+3)= frac{27(b^2+4b+4)}{b} :frac{6+3b}{b}=\\= frac{27(b+2)^2}{b} cdot frac{b}{3(2+b)} = frac{27(b+2)}{3} =9(b+2)=9(-frac{4}{9}+2)=\\=9cdot frac{-4+18}{9}=14$