Question

Решите уравнения
1)-5х+3(3+2х)=7
2)2х-3(7-2х)=3
(Х+3)^2-х^2=33

Answer 1

-5х+3(3+2х)=7
-5x+9+6x-7=0
x=7-9
x=-2

2х-3(7-2х)=3
2x-21+6x=3
8x=3+21
8x=24
x=3

$(x+3)^{2}- x^{2} =33$
$x^{2} +6x+9- x^{2} =33$
$6x=33-9$
$6x=24$
$x frac{24}{y}$
$x=4$