Question

$frac{2x ^{2}-2 }{3x^{2}+6x+3}$

Answer 1

(2х²-2)/(3х²+6х+3)=2(х-1)(х+1)/3(х²+2х+1)=2(х-1)(х+1)/3(х+1)²=
2(х-1)/3(х+1)